(2x+3)^2-x-1=(2x+5)(2x-5)

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Solution for (2x+3)^2-x-1=(2x+5)(2x-5) equation: 



(2x+3)^2-x-1=(2x+5)(2x-5)

We move all terms to the left:

(2x+3)^2-x-1-((2x+5)(2x-5))=0

We add all the numbers together, and all the variables

-1x+(2x+3)^2-((2x+5)(2x-5))-1=0

We use the square of the difference formula

4x^2-1x+(2x+3)^2+25-1=0

We add all the numbers together, and all the variables

4x^2-1x+(2x+3)^2+24=0

We move all terms containing x to the left, all other terms to the right

4x^2-1x+(2x+3)^2=-24

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